|Website:||website containing additional information|
|Period:||period 3 (week 6 through 15, i.e., 3-2-2020 through 9-4-2020; retake week 27)|
|Participants:||up till now 127 subscriptions|
|Schedule:||Official schedule representation can be found in MyTimetable|
Big Data is as much a buzz word as an apt description of a real problem: the amount of data generated per day is growing faster than our processing abilities. Hence the need for algorithms and data structures which allow us, e.g., to store, retrieve and analyze vast amounts of widely varied data that streams in at high velocity.
In this course we will limit ourselves to data mining aspects of the Big Data problem, more specifically to the problem of classification in a Big Data setting. To make algorithms viable for huge amounts of data they should have low complexity, in fact it is easy to think of scenarios where only sublinear algorithms are practical. That is, algorithms that see only a (vanishingly small) part of the data: algorithms that only sample the data.
We start by studying PAC learning, where we study tight bounds to learn (simple) concepts almost always almost correctly from a sample of the data; both in the clean (no noise) and in the agnostic (allowing noise) case. The concepts we study may appear to allow only for very simple – hence, often weak – classifiers. However, the boosting theorem shows that they can represent whatever can be represented by strong classifiers.
PAC learning algorithms are based on the assumption that a data set represents only one such concept, which obviously isn’t true for almost any real data set. So, next we turn to frequent pattern mining, geared to mine all concepts from a data set. After introducing basic algorithms to compute frequent patterns, we will look at ways to speed them up by sampling using the theoretical concepts from the PAC learning framework.
The slides completed by your own lecture notes are in principle all you need. Background reading material is, however, also available:
|Minimum effort to qualify for 2nd chance exam:||Om aan de aanvullende toets te mogen meedoen moet de oorspronkelijke uitslag minstens 4 zijn.|